Elevator Mechanic Practice Exam

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What is the maximum voltage drop that can occur across a 500-watt resistor carrying 2 amps of current?

  1. 125 volts

  2. 250 volts

  3. 500 volts

  4. 1000 volts

The correct answer is: 250 volts

To determine the maximum voltage drop across a resistor, Ohm's law can be applied, which states that voltage (V) equals current (I) times resistance (R). First, we find the resistance of the resistor using the formula for power: Power (P) = Voltage (V) × Current (I). Rearranging this gives us Voltage (V) = Power (P) / Current (I). Given a power of 500 watts and a current of 2 amps, the voltage across the resistor can be calculated as follows: V = P / I = 500 watts / 2 amps = 250 volts. This indicates that the maximum voltage drop across the 500-watt resistor carrying 2 amps of current is indeed 250 volts. The correct answer reflects a proper understanding of the relationship between power, voltage, and current in this context.

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